**SfC Home > Arithmetic > Algebra >**

# Derivation of Quadratic Formula

by Ron Kurtus (revised 9 March 2013)

A quadratic equation (**ax ^{2} + bx + c = 0**) can be solved for

**x**by using the

*:*

**quadratic formula**

x = [−b ± √(b^{2}− 4ac)]/2a

The * derivation* of that formula was done by some clever manipulation of the elements in the quadratic equation. The best way to see where the formula came from is by working backwards to establish the quadratic equation. Then you can see the steps to take to derive the quadratic formula.

Questions you may have include:

- What are the steps working backwards?
- What are the steps to get to the formula?
- How do you handle the square root?

This lesson will answer those questions.

## Working backwards

Start with the quadratic formula and put it in the form of the quadratic equation:

x = [−b ± √(b^{2}− 4ac)]/2a

Multiply both sides of the equal sign by **2a**

2ax = −b ± √(b^{2}− 4ac)

Add **b** to both sides

2ax + b = ± √(b^{2}− 4ac)

Square both sides of the equal sign

(2ax + b)^{2}= b^{2}− 4ac

4a^{2}x^{2}+ 4abx + b^{2}= b^{2}− 4ac

Subtract **b ^{2}** from both sides

4a^{2}x^{2}+ 4abx = − 4ac

Add** − 4ac** to both sides

4a^{2}x^{2}+ 4abx + 4ac = 0

Divide by **4a**

ax^{2}+ bx + c = 0

## Start from equation

Knowing the steps, you can start from the quadratic equation to get the formula:

ax^{2}+ bx + c = 0

Multiply both sides of the equal sign by **4a**

4a^{2}x^{2}+ 4abx + 4ac = 0

4a^{2}x^{2}+ 4abx = − 4ac

4a^{2}x^{2}+ 4abx + b^{2}= b^{2}− 4ac

Factor **4a ^{2}x^{2} + 4abx + b^{2}** to get

**(2ax + b)**

^{2}

(2ax + b)^{2}= b^{2}− 4ac

## Taking the square root

When you get to **(2ax + b) ^{2} = b^{2} − 4ac**, you want to take the square root of each side of the equal sign.

Note that both **(2ax + b)*(2ax + b)** and **[−(2ax + b)]*[−(2ax + b)]** equal **(2ax + b) ^{2}**.

That means that the square root can be either plus (+) or minus (−). Thus:

x = [−b ± √(b^{2}− 4ac)]/2a

The derivation is complete.

## Summary

You can see the steps to derive the quadratic formula

**x = [−b ± √(b ^{2} − 4ac)]/2a** by first going backwards to get the quadratic equation (

**ax**). Then you can reverse the steps to go from the equation to the formula. When you take the square root, you need to realize that plus or minus factors can be used.

^{2}+ bx + c = 0Go step by step

## Resources and references

### Websites

### Books

## Questions and comments

Do you have any questions, comments, or opinions on this subject? If so, send an email with your feedback. I will try to get back to you as soon as possible.

## Share

Click on a button to bookmark or share this page through Twitter, Facebook, email, or other services:

## Students and researchers

The Web address of this page is:

**www.school-for-champions.com/algebra/
quadratic_formula_derivation.htm**

Please include it as a link on your website or as a reference in your report, document, or thesis.

## Where are you now?

## Derivation of Quadratic Formula